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Inegration Question help! (1 Viewer)
- Thread starter SGSII
- Start date
lochnessmonsta
Booging
- Joined
- Apr 18, 2012
- Messages
- 157
- Gender
- Male
- HSC
- 2013
- Uni Grad
- 2017
Do a quick sketch of the graph or visualise it in your head. In this case the area will be all above the x axis so no absolute value signs are needed.
Then use simultaneous equations to find the limits, in this case from x=-1 to x=1
Then simply integrate [2 - x^2 - (x^2)]
We get the integral equalling [2x - 2/3*x^3] from -1 to 1
Substituting we get [2-2/3 - (-2+2/3)] = 8/3 units squared
Then use simultaneous equations to find the limits, in this case from x=-1 to x=1
Then simply integrate [2 - x^2 - (x^2)]
We get the integral equalling [2x - 2/3*x^3] from -1 to 1
Substituting we get [2-2/3 - (-2+2/3)] = 8/3 units squared
Thank you!
I have another quick question that I find that im having difficulties on:
View attachment 27931
Like how would I integrate it if its a fraction like the one above?
Please help!
My half yearlies on this is tmrw
I have another quick question that I find that im having difficulties on:
View attachment 27931
Like how would I integrate it if its a fraction like the one above?
Please help!
My half yearlies on this is tmrw
RealiseNothing
what is that?It is Cowpea
Split up the fraction:Thank you!
I have another quick question that I find that im having difficulties on:
View attachment 27931
Like how would I integrate it if its a fraction like the one above?
Please help!
My half yearlies on this is tmrw