integrating trig functions (1 Viewer)

[kr73114]

inegrate: 0-pi/4 [sin2xcos2x.dx]
i know you could use reverse chain rule but this question says use the compund angle formula

 

[Bored Of Fail 2]

inegrate: 0-pi/4 [sin2xcos2x.dx]
i know you could use reverse chain rule but this question says use the compund angle formula

use double angle formula for sin2x

sin2x= 2sinxcosx therefore sinxcosx = (1/2) sin(2x)

therefore sin(2x)cos(2x) = (1/2) sin(4x) now its easy to integrate

= -(1/8) [cos(4x)] between the limits etc etc

 

[hscishard]

1/2 integral 2sin2xcos2x
and then it would be integrate sin4x