Slide Rule said:
No. It would go to the right. There is less pressure there, which is where it wants to go.
You've increased pressure, so it wants to decrease pressure. It can do this by going forwards because there's only 1 mole on the right compared to 2 on the left.
Oh, and since pressure is proportional to temperature, would increasing the temperature also cause the equilibrium to go to the right, in this case?
Misplaced rhetoric. The reaction is exothermic in the forward direction, therefore equilibrium will shift in the heat-absorbing, or endothermic direction, and H2CO3 will decompose to CO2 (By LCP, eqm shift to left). Pressure, in the sense of the total pressure acting on the system, and not of [CO2] (though temperature changes do alter the solubility of CO2, and, therefore, concentration), is inversely proportional, not directly proportional, to temperature; though, this take is unnecessarily recondite. If you picture an appreciation in temperature as an appreciation in the KE of particles, it makes sense that these particles will, because of their increased mobility, occupy larger volumes. Since an increase in volume = a decrease in pressure, temperature has an inverse relationship to pressure.