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Math (1 Viewer)

Thread starter hihihi
Start date Jul 11, 2016

H

hihihi

Member

#1

INDEFINITE INTEGRAL (no bounds):

function: f(x) = 1/(4-x^2) * dx

i.e. four minus 'x' squared on the denominator as a whole

thx

leehuan

Well-Known Member

#2

$\text{This integral is not in the Ext 1 course }\int \frac{1}{4-x^2}dx$

H

hihihi

Member

#3

oh k, never knew whoops,

whats the answer?

D

Drongoski

Well-Known Member

#4

$\int \frac {1}{4 - x^2} dx = \int (\frac {1}{(2-x)(2+x)}) dx = \frac {1}{4}\int (\frac {1}{2-x} + \frac {1}{2+x})dx = \\ \\ \frac {1}{4}(ln |2+x| - ln |2-x|) + C$

Last edited: Jul 15, 2016

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