• Best of luck to the class of 2024 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page
MedVision ad

Maths Assignment- Various Questions (1 Viewer)

Itike

New Member
Joined
Feb 23, 2007
Messages
17
Gender
Male
HSC
2007
Hi, I need help on the following questions in my maths assignment:
1) The elevation to the top of a high rise building at a place X due west of it is 78º and at a place Y due south of X the elevation is 58º. If the distance from X to Y is 200 metres find the height of the building.<O:p
<O:p></O:p>
2) Show that (Sin A)/(Cos A + Sin A) + (Sin A)/(Cos A – Sin A) = Tan2A<O:p
<O:p></O:p>
3) The angle between the lines y=mx and y=x is 30º. Find the exact value of m.<O:p
<O:p></O:p>
4) The point P (x,y) moves on a path such that’s its distance from a point S(3,5) as the same as its perpendicular distance from the line y=-3. Show that the equation of the path P is (x-3)<SUP>2</SUP>=16(y-1)
<O:p></O:p>
5) If (x+1) is a factor of the polynomial P(x)= 2x<SUP>4</SUP>-2x<SUP>2</SUP>-a, find the value of a.<O:p
<O:p

For Qn 5 I get a=1 but I don’t think that that is right.<O:p
 

cl3nta

Member
Joined
Apr 8, 2006
Messages
247
Location
ooooo
Gender
Male
HSC
2007
Hey

I only did 2,3,5
I didn't look at 1 and didn't spend enough time on 4 to be of much help. Here are the solutions
Q2)
LHS= SinA/(CosA + SinA) + SinA/(CosA - SinA)
=SinA(CosA - SinA) + SinA(CosA + SinA)/(CosA + SinA)(CosA - SinA)
=SinACosA - Sin^2A + SinACosA + Sin^2A/(CosA + SinA)(CosA - SinA)
=2SinACosA/Cos^2A-Sin^2A
=Sin2A/Cos2A
=Tan2A
=RHS

Q3)
exact value of tan30 I think is root3/3 but I can't remember off the top of my head so check this up in one of your textbooks.

Q5)
Using some thm,

P(-1)=0
therefore,
=2(-1)^4 -2(-1)^2-a = 0
=2-2-a=0
hence
-a=0
so a=0

Hope this helps good luck with the assignment
 

Itike

New Member
Joined
Feb 23, 2007
Messages
17
Gender
Male
HSC
2007
Thanks for the help guys that has been really usefull
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top