Multiple Choice Answers (1 Viewer)

[Steven12]

For the battery Q (15 I think) I just imagined putting a battery into my digital camera, and which side was +, which was -... I think it worked

thats exactly what i did, -----now which way do i put the battery in, think of the signs-----

 

[Will Toe]

So would this be a correct solution set:

Q1. A
Q2. A
Q3. B
Q4. B
Q5. C
Q6. D
Q7. D
Q8. D
Q9. A
Q10. C
Q11. A
Q12. C
Q13. C
Q14. A
Q15. B

????????

 

[Managore]

Everyone state their MC marks here, perhaps, as well, since it's becoming easy to see which answers are correct.

I *think* I got 12/15, getting 9, 10 and 12 wrong.

1 A
2 A
3 B
4 B
5 C
6 D
7 D
8 D
9 D (Wrong, answer is A)
10 A (Wrong, answer is C)
11 A
12 D (Wrong, what is the answer?)
13 C
14 A (*might* be wrong, answer *might* be D)
15 B

 

[bhavo]

isnt the cathode the negative terminal??? therefore the answer to 15 id d not b??????


neways here are my solns:

1. a- duh
2. a - pretty obvious
3. b - copper is the only ion of those we have studied so this was straight forward
4. b - isomers, nothing else
5. c - basic knowledge
6. d - CCB is in d
7. d - meh
8. d - obvious tropo is the lowest and the strotos is above it
9. d - mol ratio is one to one, for both NO and O3, the greatest volume is therefore the one which is multiplied by the greatest number of moles, that being the mols of NO (0.66/30 = 0.022). when multiplied by 22.71 this gives ~0.05L
10. c - basic Le Chats knowledge
11. a - nuff said on it
12. c - NH4 has a CCB, and the only way that will happen is if it gains a H+, which of those possiblities, only HF can provide
13. c - 2012kj/mol is quite big, do the calcs, and im pretty sure the answer is c
14. a - if u look on the data sheet, its the metals at the top (right coloumn only) starting wif K which are easiest to oxidise. if u do the claculations using the potentials, you will find that when y and z are both reduced at the cathode, they must produce positive voltages, therefore must be BELOW lead on the table. Therefore, they are the hardest to oxidise, and therefore come first on the list OF INCREASING EASE
15. d - like i said at the top, its either b or d, but from wot i gather, the cathode is negative.


correct me if im wrong any where. i wana have an idea botu wot i got as well.

 

[Rowlooooooooooo]

So would this be a correct solution set:

Q1. A
Q2. A
Q3. B
Q4. B
Q5. C
Q6. D
Q7. D
Q8. D
Q9. A
Q10. C
Q11. A
Q12. C
Q13. C
Q14. A
Q15. B

????????

If it is i got every single one of them right

 

[Rowlooooooooooo]

i retire from my attempts at explanation my head hurts

 

[Managore]

Unless there's some ACTUAL explination as to why 14 is A or D no one will ever get anywhere in this argument.

 

[Managore]

And it's "duh", not "dah"

 

[Will_Sparky]

Here are my answers,

I really don't want to know if they're right or wrong

A
A
B
A
A
D
D
A
D
C
A
B
B
D
C

Too many a's

 

[Heks12]

wait, i dont get this....
Q14: z is the most reactive isn't it? (i.e. most easily loses electrons, hence is most easily oxidised)? So if its INCREASING ease of oxidation, then shoudnt it come last in the line? everyone seems to have chosen "a", so what have i done wrong?

 

[Rowlooooooooooo]

heks is right im wrong, d is right

 

[Heks12]

and 15 is b, id be almost positive about that. just go look at an actual AA battery - the pointy bit is marked positive(hence cathode), the flat bit is negative. the casing of the battery is the anode.

 

[The Bograt]

wait, i dont get this....
Q14: z is the most reactive isn't it? (i.e. most easily loses electrons, hence is most easily oxidised)? So if its INCREASING ease of oxidation, then shoudnt it come last in the line? everyone seems to have chosen "a", so what have i done wrong?

You haven't done anything wrong, the answer is D

 

[The Bograt]

and 15 is b, id be almost positive about that. just go look at an actual AA battery - the pointy bit is marked positive(hence cathode), the flat bit is negative. the casing of the battery is the anode.

Yeah 15 is B for sure, learnt it this morning

 

[fr0ggy]

1 A
2 A
3 B
4 B
5 C
6 D
7 D
8 D
9 A
10 C
11 A
12 C
13 C
14 A
15 B

 

[Rowlooooooooooo]

so did anyone get them all right?
i got 14/15

 

[tennille]

wat are the answers?

 

[tennille]

i got a, a, b, b, c, d, d, d, a, c, a, a (guessed that), b, d, b

 

[Gesus]

Oh yeah, Mr. I ace'd the multichoice sitting right here

 

[Sanchez__]

1A
2A
3B
4B
5C
6D
7D
8D
9A
10C
11A
12C
13C
14D
15B

is the same as what I got, I if that is right I got 15/15. I think they are all right looking at them again and looking at what other people said. 14 is D beacuase negative termanal oxidises I believe, so x less oxidising than Pb, Pb less than y and Pb less than z. pb and z has greater voltage than PB with y so z is stronger oxidant. Therefore the order of INCREASING EASE OF OXIDATION x, Pb, y, z. Since x least likely to oxidise and z is most. Best I can come up with to explain.