n00bie complex number q's (2 Viewers)

[Xayma]

Originally posted by :: ryan.cck ::
after that apply demoivres... [rcis@]^n = r^ncis(n@)

and then put it back into cartesian (rectangular) form

 

[KeypadSDM]

I dunno, is one of the 77th roots of -sqrt(3)/2 - i/2, sqrt(3)/2 - 1/2i

 

[Xayma]

Originally posted by Slide Rule
Am I on crack or is the answer just -sqrt(3)/2 - i/2?

Yeah thats the answer, or at least according to my calculator.