MedVision ad

Polynomial Question Help (: (1 Viewer)

lisarh

Member
Joined
Jul 22, 2007
Messages
112
Location
Sydney
Gender
Female
HSC
2009
A monic cubic polynomial when divided by (x²+4) leaves a remainder of (x+8) and when divided by x leaves a remainder of -4.

Find the polynomial in the form ax³+bx²+cx+d.
 

M@ster P

Member
Joined
Feb 9, 2008
Messages
619
Gender
Male
HSC
2009
are you sure its not (x^2 - 4) because it will make the question alot easier.
 

samwell

Member
Joined
Nov 19, 2007
Messages
400
Gender
Male
HSC
2008
since the polynomial is monic a=1 therfore use long dovision to divide polynomial ax³+bx²+cx+d by (x²+4) and u should get the remainder as [c-4a]x +4b which is equal to x+8. now c-4a=1 and 4b=8 then solve the eqn bcoz u noe that a=1. hope that made sense
 

lisarh

Member
Joined
Jul 22, 2007
Messages
112
Location
Sydney
Gender
Female
HSC
2009
M@ster P said:
are you sure its not (x^2 - 4) because it will make the question alot easier.
Yeah, the qu is (x^2+4), but it could be a typo on my sheet if you say so.

PS, hey! you go DLS, I'm from MSJ x]
 
Last edited:

samwell

Member
Joined
Nov 19, 2007
Messages
400
Gender
Male
HSC
2008
lisarh said:
Yeah, the qu is (x^2+4), but it could be a typo on my sheet if you say so.

PS, hey! you go DLS, I'm from MSJ x]
read the definition of a monic polynomial.
 

Rampager

Member
Joined
Jun 4, 2008
Messages
100
Gender
Male
HSC
2008
samwell said:
since the polynomial is monic a=1 therfore use long dovision to divide polynomial ax³+bx²+cx+d by (x²+4) and u should get the remainder as [c-4a]x +4b which is equal to x+8. now c-4a=1 and 4b=8 then solve the eqn bcoz u noe that a=1. hope that made sense
I think you miss a step :)


........... _ax_+_b_______
(x²+4)/ ax³+bx²+cx+d
.............ax³ + 4ax
....................bx²+cx+d - 4ax
....................bx² + 4b
r. cx + d - 4ax - 4b

Remainder = x[c-4a] + d - 4b = x + 8
c - 4 = 1 .............. d - 4b = 8
c = 5 .............. d - 4b = 8

To find d

Divide ax³+bx²+cx+d by x.
Remainder = d = -4

-4 -4b = 8
b = -3

Polynomial is: x³-3x²+5x-4
 
Last edited:

samwell

Member
Joined
Nov 19, 2007
Messages
400
Gender
Male
HSC
2008
Rampager said:
I think you miss a step :)


........... _ax_+_b_______
(x²+4)/ ax³+bx²+cx+d
.............ax³ + 4ax
....................bx²+cx+d - 4ax
....................bx² + 4b
r. cx + d - 4ax - 4b

Remainder = x[c-4a] + d - 4b = x + 8
c - 4 = 1 .............. d - 4b = 8
c = 5 .............. d - 4b = 8

To find d

Divide ax³+bx²+cx+d by x.
Remainder = d = -4

-4 -4b = 8
b = -3

Polynomial is: x³-3x²+5x-4
Thanks
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top