• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

pulley question (2 Viewers)

wizzkids

Well-Known Member
Joined
Jul 13, 2016
Messages
339
Gender
Undisclosed
HSC
1998
Geez, this is a wacko question. Where did you get it?
One way to solve the problem is to treat it as a lumped system. Determine the total moving mass of the system, determine the net force on the system, and from that work out the acceleration of the whole system. Then knowing the acceleration of the whole system, you can easily determine the net force acting on each part of the system from Newton's Second Law.
 
Last edited:

kkk579

hello
Joined
Jul 24, 2021
Messages
1,673
Location
Sydney, Australia
Gender
Female
HSC
2025
Geez, this is a wacko question. Where did you get it?
One way to solve the problem is to treat it as a lumped system. Determine the total moving mass of the system, determine the net force on the system, and from that work out the acceleration of the whole system. Then knowing the acceleration of the whole system, you can easily determine the net force acting on each part of the system from Newton's Second Law.
Thats what i did and one of the following qs were asking for the acceleration of block m1 which i got correct so i have no clue how i have possibly gotten part a wrong if all it is is multiplying that acceleration by the mass of m2
 

kkk579

hello
Joined
Jul 24, 2021
Messages
1,673
Location
Sydney, Australia
Gender
Female
HSC
2025
Geez, this is a wacko question. Where did you get it?
One way to solve the problem is to treat it as a lumped system. Determine the total moving mass of the system, determine the net force on the system, and from that work out the acceleration of the whole system. Then knowing the acceleration of the whole system, you can easily determine the net force acting on each part of the system from Newton's Second Law.
Also i think this q was either from a syd grammar or syd boys y11 internal
 

Users Who Are Viewing This Thread (Users: 0, Guests: 2)

Top