MedVision ad

Q14 (1 Viewer)

crazy_paki123

Well-Known Member
Joined
Nov 3, 2011
Messages
1,129
Gender
Male
HSC
2012
the answer is k<-32, you draw a horizontal lone (k=-32) which is the last time the line intersects the quartic as it is the min y value thus under it there are no graphical solutions due to no intersections. i did a similar question with my tutor the day before the exam :L
 

gr_111

Member
Joined
May 2, 2012
Messages
162
Gender
Male
HSC
2012
the answer is k<-32, you draw a horizontal lone (k=-32) which is the last time the line intersects the quartic as it is the min y value thus under it there are no graphical solutions due to no intersections. i did a similar question with my tutor the day before the exam :L
sack your tutor mate, its definitely k>32.
 

narenkumar

New Member
Joined
Oct 27, 2011
Messages
5
Gender
Male
HSC
N/A
Did we have to write it as a fraction.
I wrote it as a decimal. How much mark will I lose.
 

lance687876

Member
Joined
Jun 13, 2012
Messages
127
Gender
Male
HSC
2012
Uni Grad
2016
the graph didn't work for me, l got a min at 0,0 and a max at -1,-5 and a max at -2,-32 so l just... drew it l guess o_O
l'm guessing l got it wrong so that's 20 marks gone in total.
wow.
never gonna underestimate an exam again.
stupid silly mistakes.
 

Timske

Sequential
Joined
Nov 23, 2011
Messages
794
Gender
Male
HSC
2012
Uni Grad
2016
the graph didn't work for me, l got a min at 0,0 and a max at -1,-5 and a max at -2,-32 so l just... drew it l guess o_O
l'm guessing l got it wrong so that's 20 marks gone in total.
wow.
never gonna underestimate an exam again.
stupid silly mistakes.
(1,-5) min
(0 , 0) max
(-2,-32) mini

thats what i got
 

RishBonjour

Well-Known Member
Joined
Aug 14, 2011
Messages
1,261
Gender
Male
HSC
2012
it looked like a normal quartic with an upside down parabola in the middle
 

Timske

Sequential
Joined
Nov 23, 2011
Messages
794
Gender
Male
HSC
2012
Uni Grad
2016
how did u get 0,0 as a maximum i couldnt differentiate it as a maximum or minimum so i wrote point of inflection T_T
Well there are two ways you could do this; differentiate again or simply sub in values to the left and right of 0.
 

baileychen

New Member
Joined
Aug 24, 2011
Messages
5
Location
cherrybrook
Gender
Male
HSC
2012
Well there are two ways you could do this; differentiate again or simply sub in values to the left and right of 0.
what was the equation again i remember differentiating again and getting 0 might have been a silly mistake
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top