Question (1 Viewer)

[highshill]

I can't upload the image but I will send the link

https://thsconline.github.io/s/?view=5228&id=0ByEFYhkkDQBKZFJTRGI5eVdvblk&n=Gosford 2012 w. sol

Question 12, page 6 part v how do you solve it

 

[jazz519]

Use m=tanx where x=180-<aoc that finds u gradient of oc which equals gradient of ab since they are parallel. Then use that value for gradient and the point b, in the y-y1=m(x-x1) formula

 

[highshill]

The only part I don't get is why do you use point b and not c

 

[InteGrand]

The only part I don't get is why do you use point b and not c

You can use point C to get the slope of the line AB (since we are told that AB is parallel to OC, so slope(AB) = slope(OC) = 1/2).

 

[highshill]

I got it jazz519 and integrated that you were trying to tell me ignore my previous question I got your point thanks. The lines are parallel and therefore the gradient is the same and we can apply the gradient to line AB.