ToO LaZy ^* n/a Joined Jan 24, 2004 Messages 2,907 Location northern beaches Gender Male HSC 2004 Jul 13, 2004 #21 ngai said: y = (x + 1)4 / x4 + 1 = 1 + (4x^3 + 6x^2 + 4x) / (x^4+1) as x approaches infinity, (4x^3 + 6x^2 + 4x) / (x^4 + 1) approach 0 so asymptote y= 1 Click to expand... ok, i get it now cheeers!
ngai said: y = (x + 1)4 / x4 + 1 = 1 + (4x^3 + 6x^2 + 4x) / (x^4+1) as x approaches infinity, (4x^3 + 6x^2 + 4x) / (x^4 + 1) approach 0 so asymptote y= 1 Click to expand... ok, i get it now cheeers!