Really Easy Motors + Generators Question (I can't do) (1 Viewer)

[User-Dependent]

I can't work the following out, any help is appreciated;

A conductor carrying 2.5A experiences a force of .6N when .4m of its length is placed in a magnetic field of intensity 0.5T.

Calculate the angle the conductor makes with the field;

The supplied answer is 17.45 degrees.

I know it involves the F = BILsin(theta) equation, sadly I can't find theta.

 

[tommykins]

回复: Really Easy Motors + Generators Question (I can't do)

Weird, i get sin@ = 6/5 and can't inverse it.

 

[User-Dependent]

Re: 回复: Really Easy Motors + Generators Question (I can't do)

Weird, i get sin@ = 6/5 and can't inverse it.

Same. I don't think you can shift sine a number over 1 (which unfortunately is 6 / 5).

17.5 degrees doesn't even get the same answer (.6N).

Maybe this question was a mistake.

 

[tommykins]

回复: Re: 回复: Really Easy Motors + Generators Question (I can't do)

Same. I don't think you can shift sine a number over 1 (which unfortunately is 6 / 5).

17.5 degrees doesn't even get the same answer (.6N).

Maybe this question was a mistake.

Yeah, it's not within the domain of the asin curve.

Best bet is the question is wrong.

 

[Riet]

Re: 回复: Re: 回复: Really Easy Motors + Generators Question (I can't do)

Yep the question must be wrong.

 

[chook 05]

maybe its to do with that ASTC circle used in maths?

like sin(@) = sin(360+@)

lol try that

 

[obimoshman1234]

could u mabye post actual uestion up like so i can see how its worded and stuff also are u 100% sure those are the given values like u have put the right measurments for them???

cause if so no way that can work out