Section I - Multiple Choice (1 Viewer)

[bleacher]

7 is wrong forgot the negative but for 5, IF cl together is 2 factorial (as a group) x 6!

 

[Skeptyks]

can't you read? -.-

swear it was D when I read it but k. fast edit ;p

 

[Skeptyks]

7 is wrong forgot the negative but for 5, IF cl together is 2 factorial (as a group) x 6!

^

 

[Nws m8]

x-coordinate:
mx2+nx1/m+n

therefore (24-4)/5
therefore 20/5
therefore 4
... wrong?

exactly , that's A!
U have B up there -.-

 

[bleacher]

4 and 5 wrong

i got same as u for 5, im pree sure its right.

 

[Raolan]

Re: General Thoughts: Mathematics Ext 1

It was pretty good! so happy, can someone confirm my answers to MC:

1. D
2. A
3. B
4. C
5. C
6. A
7. C
8. D
9. D
10. B

1 is C. Use Wolfram if you want proof.
2 is correct.
3 is correct.
4 is correct.
5 I put D, but I'm terrible at probability so you're probably correct. I figured there are 7 total letters but L and C only count as one, so 2 (ways of LC) * 6! (total of 6 objects)
6 is correct.
7 is correct.
8 is probably correct, I missed it until the last second and accidentally circled B because I couldn't see the question.
9 is correct.
10 probably correct.

 

[aaron_syd]

You guys serious? I probs got sum wrong then I got a few different answers:

C
A
B
A
D
A
C
D
D
B

 

[SandyS1995]

Why isn't 5 D? :s

 

[LlamaBoi]

4: If its C then the amplitude is indeed 2 but the period is 6pi, meaning it would be restricted to 3pi, not 3pi/2
5: Group the C and L together so theres 6! ways of arranging those letters but the C and L can move in between each other 2 ways, hence 2 x 6!, so D

 

[Nws m8]

i got same as u for 5, im pree sure its right.

5 is C

 

[Timske]

Re: General Thoughts: Mathematics Ext 1

1 is C. Use Wolfram if you want proof.
2 is correct.
3 is correct.
4 is correct.
5 I put D, but I'm terrible at probability so you're probably correct. I figured there are 7 total letters but L and C only count as one, so 2 (ways of LC) * 6! (total of 6 objects)
6 is correct.
7 is correct.
8 is probably correct, I missed it until the last second and accidentally circled B because I couldn't see the question.
9 is correct.
10 probably correct.

5 is D. 2*6!

 

[Nws m8]

4: If its C then the amplitude is indeed 2 but the period is 6pi, meaning it would be restricted to 3pi, not 3pi/2
5: Group the C and L together so theres 6! ways of arranging those letters but the C and L can move in between each other 2 ways, hence 2 x 6!, so D

yeah ?? so it is C!

 

[Nws m8]

4: If its C then the amplitude is indeed 2 but the period is 6pi, meaning it would be restricted to 3pi, not 3pi/2
5: Group the C and L together so theres 6! ways of arranging those letters but the C and L can move in between each other 2 ways, hence 2 x 6!, so D

therez total 7, C L = 2! rest 5=5!

therefore = 2 x 5!

 

[kliro_10]

1 C
2 A
3 C (stupid)
4 C
5 D
6 A
7 C
8 D
9 D
10 B

 

[LlamaBoi]

yeah ?? so it is C!

No, I said IF it was C then it would be 6pi and be restricted to 3pi, but its restricted to 3pi/2 so it ends up being D

 

[bleacher]

its 5 letters and a group, so 6!, u prob forgot to do the group as well

 

[kliro_10]

therez total 7, C L = 2! rest 5=5!

therefore = 2 x 5!

no, LlamaBoi is correct

 

[Nws m8]

Re: General Thoughts: Mathematics Ext 1

1. A
2. B
3. b
4. b
5. b
6. c
7. c
8. d
9. a
10. a

^^^^^ These are the correct answers

 

[Raolan]

Re: General Thoughts: Mathematics Ext 1

5 is D. 2*6!

Awesome. The suckiest person ever at probability got one right.

ch'yeah.

 

[Timske]

therez total 7, C L = 2! rest 5=5!

therefore = 2 x 5!

OLYMPIC - 7 LETTERS
Wrong. C and L = 2! , this counts as 1 + 5 remaining letters = 6

Thus, 2*6!