some1 noe answer for the last question (1 Viewer)

[ying123123]

the quesiton was about taht momentum thing i think

 

[seadonkey]

1.666 x 10^-27

 

[darkwarrior2]

is it p=mv?

 

[jarro_2783]

yes that is correct. Was that the one with the protons. You were meant to use the two force equations to end up with mv = qBr or something like that.

 

[sweet_chick]

yea p=mv but the equating some force you could get another expression

 

[ying123123]

okay this is wat i got
dont think if its right
centripetal force (the result had and radius so yeah)
and f=qvb
mv=p
then p=qrB

 

[ying123123]

and wat did u let the proton at rest ?
wat was it u let v=c?
another guess

 

[jarro_2783]

you needed to use einsteins mass dilation formula.

 

[Captain Gh3y]

Ok, here's how it worked:

(i) The particle is in a magnetic field, and also has centripetal force (the hint was 'circular path with radius...')

so F = qvB = mv²/r

Rearranging that, you get mv = qBr.


(ii) All of the values for the above were given, except for q, which is 1.602x10¹⁹C (from data sheet), so simple substitution to get the mass of a proton, as observed by someone standing outside the accelerator and watching it move.

(iii) Apply the mass dilation formula in reverse, ie.
m_v = m_o/√(1-v²/c²)
m_v is what you found in part (ii), so rearranging
m_o = m_v*√(1-v²/c²)

Then you substituted in the velocity and your answer to part (ii), and got a mass, a bit smaller than the value in part (ii).

 

[ying123123]

yeah i got tat except for iii)

 

[richz]

yep yep nice work captian

 

[Haku]

i ran out of time and didn't get any of that. couldn't think when i am short on time....

 

[thunderdax]

The answer for (iii) should have matched with the data sheet to 3 significant figures.

 

[Captain Gh3y]

The answer for (iii) should have matched with the data sheet to 3 significant figures.

Really?

My final answer for (iii) was similar to seadonkey's, somewhere near 1.66e-27... can't remember exactly.

 

[thunderdax]

yeah, it was 1.67e-27 which is the same as the data sheet to 3 significant figs.

 

[richz]

Really?

My final answer for (iii) was similar to seadonkey's, somewhere near 1.66e-27... can't remember exactly.

yeah, it was eql to 1.666e-27 so 3SF = 1.67e-27

 

[jake2.0]

how come no one here took into account the weight force on the proton???

mind you i ended up getting the same answer

 

[shobadaynature]

woot! i got it!! gee it reli made me dive into equations and think to integrate these stuff together...

 

[samaccount123]

Particle accelerators aren't THAT small..I didn't understand this qstn much to get it I think..

 

[samaccount123]

Particle accelerators aren't THAT small..I didn't understand this qstn much to get it I think..

Oh yeah, darn..its travelled in a bubble chamber even though the cyclotron or something is as big as it is and the hydrogen deflects the proton/s..ugh