No, its:fullonoob said:Root: root3=3x
x=root3 over 3
No...jellybelly08 said:No, its:
root3=root(3*x^2)
=root3*x
so x=1
Is the question askingfullonoob said:No...
if its root then it should b:
root3= 3x (square cancel root)
x = root 3 over 3
am i correct?
jellybelly08 said:Is the question asking
3=3*(x^2)
OR
3=(3*x)^2
???
So basically 3 = 9*x^2.fullonoob said:2nd one
(3x)^2
Notice the extra 'fullonoob said:and another noob question
can u differentiate twice?e.g. x^3 - x^2
y'=3x^2-2x
differentiate agn
y''=6x-2
can u do that?
yes. you can do this.fullonoob said:and another noob question
can u differentiate twice?e.g. x^3 - x^2
y'=3x^2-2x
differentiate agn
y'=6x-2
can u do that?
1) y'=6x-2fullonoob said:and another noob question
can u differentiate twice?e.g. x^3 - x^2
y'=3x^2-2x
differentiate agn
y'=6x-2
can u do that?
3 = (3x)2fullonoob said:find x when:
3=(3x)^2
f(x) = x3 - x2fullonoob said:and another noob question
can u differentiate twice?e.g. x^3 - x^2
y'=3x^2-2x
differentiate agn
y'=6x-2
can u do that?
y" actually.x.Exhaust.x said:1) y'=6x-2
2) y'=6
Youonly do that to find the second derivative or find the points of inflexion.fullonoob said:and another noob question
can u differentiate twice?e.g. x^3 - x^2
y'=3x^2-2x
differentiate agn
y'=6x-2
can u do that?