+1jjo said:So happy its over.
I had no problems at all until the last part of Q9, where we had to find the distance below the axis. Spent about 5 mins on it, nothing came to me, so went on to Q10.Lovell said:I thought it was good untill question 9 and 10.
SameeeLovell said:I thought it was good untill question 9 and 10.
You can't, you were meant to change it to (e^y + 2).UncoKane said:Sameee
Question 9 and 10 were so hard.
I forgot how to integrate logs..?
I was thinking I had to change it to something... but I completely forgot.davOmeter said:You can't, you were meant to change it to (e^y + 2).
HOLY SHIT I DID THATdavOmeter said:You can't, you were meant to change it to (e^y + 2).
you didn't need to integrate the log in q 10 (not taught in 2U). you needed to minus the area of the curve between the y-axis from the of the rectangle (7ln5)UncoKane said:Sameee
Question 9 and 10 were so hard.
I forgot how to integrate logs..?
That's what I diddavOmeter said:You can't, you were meant to change it to (e^y + 2).
Oh... :lSmeegen999 said:you didn't need to integrate the log in q 10 (not taught in 2U). you needed to minus the area of the curve between the y-axis from the of the rectangle (7ln5)
I found that out right after the exam >.<"davOmeter said:You can't, you were meant to change it to (e^y + 2).
I proved similar triangles to get MP=s(l-x)/x. Is there a quicker way?Kiwijnr said:easy paper...except for 10 bi....i had no clue...
nup, i think thats the only way, or the only way i saw it...i guess it was pretty long but wasn't too bad if u know wat i meanahhliss said:I proved similar triangles to get MP=s(l-x)/x. Is there a quicker way?