MedVision ad

Urgent Help: Maths ...look at this thread (1 Viewer)

bing005

bing005
Joined
Mar 20, 2005
Messages
6
Gender
Male
HSC
2005
Hey can some really smart person do an analysis of past papers (Eg 94-04) and tell me what types of questions always come up... It would help me heaps cause i would know what to study....

Thanks dudes!
 

Slidey

But pieces of what?
Joined
Jun 12, 2004
Messages
6,600
Gender
Male
HSC
2005
It would be more beneficial for you to do the analysis yourself: you can understand the questions better that way, as well as get practice doing them.

If anybody does do one, be sure to post it here. :)
 

bing005

bing005
Joined
Mar 20, 2005
Messages
6
Gender
Male
HSC
2005
Mate im the worst possible studier ever..... i really need some smart person to do it.....i got 24% in my trials
 

bing005

bing005
Joined
Mar 20, 2005
Messages
6
Gender
Male
HSC
2005
theres not enought time to do it myself...... i left it to late ..... hehehehehe
 

rama_v

Active Member
Joined
Oct 22, 2004
Messages
1,151
Location
Western Sydney
Gender
Male
HSC
2005
Well,
The last questions gonna involve differentiation and minimisation/maximisation
There's always co-ordinate geometry (like equation of lines and intersections etc. )
Geometry is in virtually every paper, usually they like to pick simlar triangles
Trig is always there too
Simple Integration and Differntiation is usually question 2 or 3 but it comes up in other areas as well, sometimes these are not so easy. e.g. rates
Simple algebra - Question 1
The questions towards the end tend to focus on appliactions of calculus to the physical world and applications of series (i.e. supperannuation, time payments etc.)
 
Last edited:

Meldrum

Banned
Joined
Oct 20, 2004
Messages
1,270
Location
Gone.
Gender
Male
HSC
2005
Yeah, Rama's right.

But also: if you get stuck, JUST THINK LOGICALLY! Draw construction lines, think outside the square (or circle as it's likely to be).
 

jemsta

I sit here alone
Joined
Apr 6, 2005
Messages
5,711
Location
O.P
Gender
Male
HSC
2005
normally trig functions like finding the area of a sector etc will be either number 9 or 10....time repayments, superannuation and compound interest
btw has anyone done the 1989 paper?? tell me what u think
 

switchblade87

Member
Joined
May 26, 2005
Messages
195
Location
Hawkesbury
Gender
Male
HSC
2005
Trig for the past 3 or so years has made up something like 25% of all the marks (30/140), so know all your trig!
 

chinkyeye

Member
Joined
Jul 1, 2005
Messages
104
Location
[KFC] Kids From Chipping Norton
Gender
Male
HSC
2005
hey can ne1 explain how to find nature of stat. poitns..stuff like that..cos ireally don't get it...cos i was doing this uqestion right..and i found da second derivative equal to zero, doesn't that mean point of inflexion occurs... i dunno but tha answer said it was a minimum..please educate me
 

rama_v

Active Member
Joined
Oct 22, 2004
Messages
1,151
Location
Western Sydney
Gender
Male
HSC
2005
Please post up the question

where f''(x) = 0, an inflexion point exists
where f''(x) >0, that point is concave up and therefore a minimum
where f''(x) <0, that point is concave down and therefore a maximum

EDIT: Like word pointed out beloe the first point f''(x) = 0 does not necessarily mean that an inflexion point exits, it merely means that there is the possibility of an inflexion point. My bad, sorry.
 
Last edited:

word.

Member
Joined
Sep 20, 2005
Messages
174
Gender
Male
HSC
2005
no.
f"(x) = 0 means theres a possible point of horizontal inflextion
you still have to check the gradient on both sides to verify that it is an inflexion

take f(x) = x4 for example
f"(0) = 0, but we know f(x) = x4 is a parabola
f'(-1) = -1, f'(0) = 0, f'(1) = 1 hence the shape \ _ / i.e. minimum
 

chin music

Member
Joined
May 16, 2005
Messages
73
Location
Bondi Beach
Gender
Undisclosed
HSC
N/A
word. said:
no.
f"(x) = 0 means theres a possible point of horizontal inflextion
you still have to check the gradient on both sides to verify that it is an inflexion

take f(x) = x4 for example
f"(0) = 0, but we know f(x) = x4 is a parabola
f'(-1) = -1, f'(0) = 0, f'(1) = 1 hence the shape \ _ / i.e. minimum
Ye i learnt that one the hard way. But ye u gotta prove it
 

goan_crazy

Hates the waiting game...
Joined
Sep 28, 2004
Messages
6,225
Location
Sydney
Gender
Male
HSC
2005
This is going to be my worst exam. Why can't maths be like legal?
If I pass, ill be over the moon!
 

rama_v

Active Member
Joined
Oct 22, 2004
Messages
1,151
Location
Western Sydney
Gender
Male
HSC
2005
word. said:
no.
f"(x) = 0 means theres a possible point of horizontal inflextion
you still have to check the gradient on both sides to verify that it is an inflexion

take f(x) = x4 for example
f"(0) = 0, but we know f(x) = x4 is a parabola
f'(-1) = -1, f'(0) = 0, f'(1) = 1 hence the shape \ _ / i.e. minimum
yeah, thats right, sorry bout that - Dont do what I did in an exam! :D
 

DeanM

Member
Joined
Jul 13, 2005
Messages
137
Location
Shellharbour
Gender
Male
HSC
2005
there is ALWAYS exponential growth and decay,
cosine / sine rule
bearing
differentiation cos, sin, tan
probability

no doubt they'll be in there
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top