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Pretty sure its D. 19.6 Is the horizontal and vertical component of the velocity, so v=sqrt(2*(19.6)^2)=27.720 is C
F=Eq, ma=Eq, a=Eq/m. The alpha particle has twice the charge, 4 times the mass, so acceleration is half.can someone explain 17? i got it right but i still dont get it hah
Yeah you're right. My mistake.Pretty sure its D. 19.6 Is the horizontal and vertical component of the velocity, so v=sqrt(2*(19.6)^2)=27.7
F=Eq, ma=Eq, a=Eq/m. The alpha particle has twice the charge, 4 times the mass, so acceleration is half.
what's 17can someone explain 17? i got it right but i still dont get it hah
Nep.Answer for 17 is D.
Uniform electric field implies constant force.
Alpha particle ~4amu
Proton ~1amu
Since f = m*a, and is constant, alpha particle mass is 4* proton, therefore it's acceleration is 1/4 of proton.
Damn. You're correct.Nep.
Charge of alpha particle is twice charge on proton, so acceleration ends up as 1/2
F = ma
F = qE
qE = ma
a = qE/m