Ask here if you need any help with the General Maths questions/ topics! :D (2 Viewers)

[mrh94]

^

 

[cute-teddy]

Hi. topic is applicaion of probability which is expected outcomes.
1) Two cards are selectec at random from a normal playing pack with replacement. This experiment is repeated 2704 times with the cards being replaced each time.
a)What is the expected numbers of times the result would be two spades?
b)What is the expected numbers of times the result would be two aces?

 

[mashups]

im pretty sure that b) is 208. 4/52 cards are aces therefore 4/52 x 2704 should give you the answer
think u then divide the answer by two as you only need two cards

 

[cute-teddy]

the answer on the back of the maths book says B) is 16

 

[mrh94]

the answer on the back of the maths book says B) is 16

What's the answer for a?
Checking to see if it's right.

 

[Leffife]

Hi. topic is applicaion of probability which is expected outcomes.
1) Two cards are selectec at random from a normal playing pack with replacement. This experiment is repeated 2704 times with the cards being replaced each time.
a)What is the expected numbers of times the result would be two spades?
b)What is the expected numbers of times the result would be two aces?

I don't do general, but anyways here

Answers for A and B are the same, but the calculation below is for (B).
P(AA) = (4/52 x 4/52) x 2704 = 16

 

[cute-teddy]

answer for a) is 169

 

[enoilgam]

a) 1/4 x 1/4 = 1/16. 2704 x 1/16 = 169. I think thats how you do it.

 

[cute-teddy]

Thank you everyone for your help

 

[mrh94]

a) 1/4 x 1/4 = 1/16. 2704 x 1/16 = 169. I think thats how you do it.

Yep, that's what I got But wouldnt it be the same for B aswell?

 

[wavess]

Oh I need help, can someone please help me:
It's the last question ( b iii)
keep getting the wrong answer

 

[p3rf3ction]

Oh I need help, can someone please help me: View attachment 26792
It's the last question ( b iii)
keep getting the wrong answer

is the answer Thursday 8am?

 

[harrietty]

Perfect timing. Topic AM3 Algebra - the answer for this is x = 6.
This probably sounds stupid, but how do you solve it?

 

[enoilgam]

Perfect timing. Topic AM3 Algebra - the answer for this is x = 6.
This probably sounds stupid, but how do you solve it?
View attachment 26795

Simplify the left hand side first then proceed from there.

 

[wavess]

is the answer Thursday 8am?

Yes it is! How'd you do it?
Idk why this is confusing me!

 

[Indoz]

Yes it is! How'd you do it?
Idk why this is confusing me!

Osaka is 16 hrs ahead, so the message is sent 6pm Wednesday denver time. + 14 hours = 8am Thursday

 

[Indoz]

Yes it is! How'd you do it?
Idk why this is confusing me!

Osaka is 16 hrs ahead, so the message is sent 6pm Wednesday denver time. + 14 hours = 8am Thursday

 

[Indoz]

Perfect timing. Topic AM3 Algebra - the answer for this is x = 6.
This probably sounds stupid, but how do you solve it?
View attachment 26795

4x/9 + 3(x+1)/9 = 5

(4x+3x+3)=45

7x = 42

x = 6

 

[wavess]

Osaka is 16 hrs ahead, so the message is sent 6pm Wednesday denver time. + 14 hours = 8am Thursday

Oh okay, thank you for your help.

 

[wavess]

I have another question, can someone help me with this question:
I just don't understand the concept of it, I get the method when I see the answer, but not the concept of it.