kepler's 3rd law
how to do dis??
Ahhh thanks Parbee!kepler's 3rd law
since they all orbit the same central body (the sun) GM/4(pi)^2 is constant
So you can equate r1^3/t1^2=r2^3/t2^2
F=nBILsin(theta)Ahhh thanks Parbee!
Can you also explain the question above above if you're not busy?
maybe im derping but uhm all the answers seem wrong, if you work backwards you find that they all give a radius thats x10^15 :/
Use (delta)x= Ux x t where (delta)x is your range and t is your time of flight
too much maffs halp me get through!
I think they're meant to be in km/s ?--> I'm getting 13.1 km/s
403 is in ms^-1, don't forget to convert to kmh^-1Wow these questions have a lot of wrong answers then. I did use Ux.t=delta x but none of the answers are correct.
For the first one I also got 403 and for the second one I'm getting 33.25
Good to know I'm not that incompetent(though it wasted a lot of my time)
maybe im derping but uhm all the answers seem wrong, if you work backwards you find that they all give a radius thats x10^15 :/
v=sqrt(GM/r)= sqrt[(6.67x10^-11 x 1.9x10^27)/(7.78x10^11 + 7.15x10^7)]=403.6ms^-1 x (10^-3)/(1/3600)= 1453 kmh^-1
Why did you substitute this ^?. Isn't M meant to be mass of the primary ie the sun not the mass of Jupiter itself?
Oh I thought we're assuming an object is orbiting jupiter at the given distanceWhy did you substitute this ^?. Isn't M meant to be mass of the primary ie the sun not the mass of Jupiter itself?
If it is orbiting the sun then this is correct (even though they didn't give the mass of the sun :L)I think they're meant to be in km/s ?--> I'm getting 13.1 km/s