No idea if this is correct. Definitely a hard one.
Attachments
-
1.2 MB Views: 25
No idea if this is correct. Definitely a hard one.
Yup nice now for a nasty one:No idea if this is correct. Definitely a hard one.
Sqrt 1+t^2/2t + 1-t^2/2t = sqrt 1/tYup nice now for a nasty one:
Actually that’s still very ugly to integrate ripSqrt 1+t^2/2t + 1-t^2/2t = sqrt 1/t
Trivial qeru forgot about tan half angle
? its cosec^2x and cot^2x not cosecx and cotx not to mention u need the dxSqrt 1+t^2/2t + 1-t^2/2t = sqrt 1/t
Trivial qeru forgot about tan half angle
Tan half angle may or may not simplify what is meant to be integrated. Dw about my scribbling lmao. Did actually forget about the ^2 haha.? its cosec^2x and cot^2x not cosecx and cotx not to mention u need the dx
Just a question. The standard way to do this integral seems to look like a page of working at least.? its cosec^2x and cot^2x not cosecx and cotx not to mention u need the dx
I see lns looks pretty legit lol.Okay here’s my answer but it looks very VERY wrong. Don’t mock me!
Definitely could simplify inside brackets but it looks decently legitOkay here’s my answer but it looks very VERY wrong. Don’t mock me!
It’s wrong. Just realised I stuffed up in my solution .Okay here’s my answer but it looks very VERY wrong. Don’t mock me!
Be back in 30mins once I type this up lol@Qeru latex a solution lol
Yup nice now for a nasty one:
Nice. I did the same initial sub then got to and used a t-sub. Your method is much better and I suspect I have made an error somewhere.Let
Let
Ill save the partial fractions working.
Drawing up a triangle we find:
So:
I could have very easily made a mistake whether in latex or just trying to evaluate to integral so let me know if you find any