the area enclosed between the parabola x^2=4ay and its latus rectum is \frac{8a^2}{3} units^3
a solid figure has its base in the xy plane, the eclipse [text]\frac{x^2}{16}+\frac{y^2}{4}=1[/tex]
cross-sections perpendicular to the x-axis are parabolas with latus rectums in the xy plane...