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Thanks guys! Bump...

FINALLY FINISHED! man this week has been hectic :S

P(x)=(x-1)(x+4)Q(x)+R(x) then sub x=1 into polynomial (then equate to -4 since P(1)=-4) then you should be able to find R(1) :)

$So you are given: $\\\\\dfrac{dv}{dt}=-8(25-t)\\\\$We separate the variables then we integrate:$\\\\\int dv=\int-8(25-t)\:dt\\\\v=-8\left[25t-\dfrac{t^2}{2}\right]+C\\\\$To find C, we sub in our initial conditions $t=0$ and $v=2500$ (remember to change in terms of cm^3!)$\\\\C=2500\\\\$So...

Agree about Tina, I mean c'mon Rachel said to Tina in Season 3 that she was gonna be the lead singer in glee club this year then in the 1st ep of this season, they just totally brushed that aside and made Blaine leader (who sings more solos compared to others) and they just accepted it :/ Quinn...

For Question 2 a), think about the properties of a rhombus and a square. A rhombus has equal sides and diagonals are perpendicular to each other and a square has these properties and also their angles are 90 degrees. Now think about how you can relate that for conditions in terms of z. Perhaps...

Hi there, I am a 2011 graduate from St George Girls High School (a top 20 selective school) and am currently studying Bachelor of Science (Advanced) at USYD, intending to major in Mathematics and Statistics. I have received Band E4 for HSC Mathematics Extension 1 and Extension 2 and have one...

Mercedes and Mike are going to appear in "The role you were born to play". I wanna see Quinn as well in later episodesXD but what's really weird is that the graduates are in the school play for Grease......Jake is basically Finn+Puck+(possibly Mike because he says he likes dancing but it is a...

It's basically the same method, it's just let's you recognise the limit easily by changing the variable. So yes I think your method works.

I agree about the new cast, and although i don't like unique that much, she offers something different compared to the other new people. Also, the rachel's love interest storyline in NY seems forced. Anyway, have you guys seen this? I cringed a little><

usually if they specify a poem, it is one of the main ones : Dulce Et Decorum Est, Futility, Anthem for Doomed Youth...

As said before, vet science has a lot of contact hours and require a lot of dedication. Your commitment statement probably requires at least one/two work experience (because my friend got in just with one) but perhaps you can volunteer/do work experience for your local vet or if you're looking...

Like in the middle of the lecture, this girl came up to the lecturer and asked him something then the lecturer finished what he was saying. Then she played the music and around 6 guys in suits stood up and the guy came in and they were all singing "All you need is love" to a girl and one of the...

A guy serenaded/professed his love to a girl in psych lecture today with people in suits with instruments and that LOL

you should have this step in your working out: \ln v =-kx+\ln V so when you exponentiate everything to find v, you have: v=e^{-kx+lnV} Now that expression should not be equal to v = e^{-kx} + V so check your working out from there.

The question did not ask for an equation involving "t" so you should NOT include it at all. When you come to step after integrating and have to find the constant C, only use the x and v conditions (NOT "t").

When we find the greatest coefficient, we are generally concerned about the magnitude of the coefficients. So technically, it should be |T_k+1 / T_k| > 1. The reason for this, is because this inequality relies on the assumption that the coefficients increase up to T_k+1 and then decrease...

oh darn someone beat me to it :P

usually semi-vertical angle means half the vertex angle of the cone if you want to interpret it that way. Hint: angle AGC is alpha+beta due to sum of int. angles equalling ext. angle. I recommend that you draw the triangles AOC and AGC separately so you can find tan (alpha) and tan (alpha+beta)...

yes you are right