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tubefed

ok i will do them on paint now :) actually, its probably best to split the Al up on the RHS, and draw both of them. People teach electron structures many different ways

Re: The Official Football Thread yeh i'm sure many will, but there will be so many scalpers selling up for big bux

Re: The Official Football Thread If its a bayern v chelsea final, what are the barca and madrid fans going to do with the tickets they bought in the final, probably start some riot.

federer has also never won gold at the olympics, i know there are much bigger things to do in the sport, but that's something he may want as well.

approximately x=0.65, but you don't have to know this. It is beyond the scope of all HSC mathematics courses and the textbook shouldn't have that question

what do you live for?

Re: Finished HSC 2011, started course but hated-have no idea what I want to study? HE what did you not enjoy about vet sci?

when their arguments are 180 degrees different

oh yeh, i read equality and inequality :) thanks

Isn't this true for any conditions? i'm trying to think of an instance where it isn't true but i can't think of one

basically, i think the tactic for me going into the exams reading time will be to find the MC questions i can do in my head and just memorise the answers and gun them straight away when writing starts

Centrifugal force does not exist

we know from this fraction, that it cannot be simplified without splitting it up, i.e the degree of the numerator is less than the denominator. Therefore, this fraction must come from an addition of two fractions. There is a possibility that the second fraction may end up only having a constant...

doesn't that only work with linear factors in the denominator?

mi scusi

<a href="http://www.codecogs.com/eqnedit.php?latex=\frac{10}{(x-1)(x^{2}+9)}\\ = \frac{a}{x-1}@plus;\frac{bx@plus;c}{x^2@plus;9}\\ =\frac{a(x^2@plus;9)@plus;(bx@plus;c)(x-1)}{(x-1)(x^2-9)}\\ taking, numerator, and, expanding, and, factorising\\ =(a@plus;b)x^2@plus;(c-b)x@plus;(9a-c)= 10\\ we now...

the answer is ln(x-1) -1/2ln(x^2+9) - 1/3tan-1(x/3) + C post working in a sec

my calc gives 5 by using that anyway :P

just put (3^99 + 5^99)^1/99 in calc :) so much easier hahaha... nah that law is awesome