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yeh thats it :)

here's a good maxima and minima question to test your ability. the cost of running a car at an average speed of v km/h is given by c=150 + (v^2/80) cents per hour Find the average speed, to the nearest km/h, at which the cost of a 500km trip is a minimum.

whenever you solve an absolute value question, you are effectively squaring both sides. eg |x|=2, x=+-2. Really we are just skipping a step, |x|=2, x^2=4, x=+-2. What do u mean by solving 'normally' anyway? you should never find limits using a table of values, unless you are fairly confident in...

where did u get this question from? when finding stationary points, you are left with the equation x^2=-ln(x) and solving this is beyond the scope of mathematics

dont forget when a is negative

<a href="http://www.codecogs.com/eqnedit.php?latex=x^3 @plus; y^3 = a^3\\*3x^2 @plus;3y^2dy/dx = 0\\*dy/dx=-x^2/y^2\\d^2y/dx^2 = \frac{-2x(y^2)-(2ydy/dx)(-x^2)}{y^4}\\ = \frac{-2xy^2@plus;2xy^2(-x^2/y^2)}{y^4}\\= \frac{-2x(1-\frac{x^2}{y^2})}{y^2}" target="_blank"><img...

for 1. we use the relationship that T2-T1=T3-T2. Put over a common denominator each side, then cross multiply and cancel terms. This will leave you with the relationship xz=y^2. We can then say that x,y and z are 3 consecutive terms of a geometric progression as T2 x T4 = (T3)^2.

porn critic. Nah, NBA point guard

on a scale of 1 to mechanics, how much does physics help with mechanics?

my tip would be go back to basics, and write down step by step what you know you have to do. Also, in the HSC exam, they can only ask locus questions about the rectangular hyperbola.

repped

yeh im getting 2secA as well

i am a convert, REP IZ LYF

just define the set to shut him up

just read the bible instead, much better read

kudos, rot in hell unfaithful people

because god=miracle=love

miracle = god. True story

god is love, do you not believe in love ?!??!?!?!?!?!?!?!?!?

GOD EXISTS IN MY HEART 4 LYF <3 <3 <3 PROVE HE DOESN'T EXIST BITCHEZZZZZ