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just realised, ive left myself open to more attack by no_arg, i bet he'll put something like this up again lol: hahahahahahaha

in maths they usually require students to put things into "exact" form and anyway, its very wrong to say ur sure somethings correct when it isnt on a site thats meant to assist those being tested on the topics discussed lucifel, ill quote u again: i completely agree, i dont see how...

im glad no_arg is gone, even though the calculator proofs werent exactly creative, they were still valid no_arg didnt accept them because he claimed rounding off caused the answers to be inaccurate, so then people calculated values exactly and he still didnt accept them he continued to...

hence, the answers differ by the constant ^π/_2√2

nice work tutor01! it can also be solved through the substitution: u² = x² + ¹/_x²

hence, no_arg is wrong comment about no_arg:

also, to stop everyone from repeating themselves over and over again i have make this point everyone has accepted that pi^4 + pi^5 is not equal to e^6 as this has been shown many times in the previous 2 threads further discussion should only be on creating new ways of making no_arg look...

lol, i find it amusing that right after a number of people proved ur argument was wrong u decided to attacking me ill quote what i put in the "Oops" thread:

maybe not, it might take some time to think up the correct ideas i tried to do it for a while and ended up asking my tutor for the solution EDIT: ok, ill remove the hint

the first person to solve this will prob be either u who_loves_maths or FinalFantasy

lol, no, there are no complex numbers used in solving the question however, thats only in the solution ive seen its possible there may be a solution that does involve using them EDIT: its a multiplication sign in the middle: int{(x^2-1)/(x^2+1) x 1/(sqrt(x^4+1))}dx...

this integration question was covered in my tut this morning, its a very interesting question and only requires 3/4u integration techniques however, solving it does require creativity: lets see if anyone can beat FinalFantasy to the solution!

lol, im not discouraging people from doing maths, what i am trying to do is get u to admit that pi^4 + pi^5 is not equal to e^6 im angry cause u claimed pi^4 + pi^5 = e^6 which is obviously wrong and hsc-er might believe it also, u keep saying that buchanans argument is invalid when its...

??? are u honestly saying that u dont think 3.14159266⁴ = 97.40909182902901737436094415467536? why dont u multiply it out on paper and see for yourself before making stupid comments buchanan's argument is completely correct and so is who_loves_maths 2 people have proved u...

π < 3.14159266 e > 2.71828182 π⁴ + π⁵ < 3.14159266⁴ + 3.14159266⁵ 3.14159266⁴ = 97.40909182902901737436094415467536 (exactly) 3.14159266⁵ = 306.0196879073435359103048143469980156588576 (exactly)...

no_arg, everyone knows that u know π⁴+π⁵ ≠ e⁶ but just incase a hsc-er comes and takes ur comments seriously: this was on: http://mathworld.wolfram.com/eApproximations.html a site from Wolfram Research hence, π⁴+π⁵ is...

i know most people know what no_arg is saying isnt true but it is possible that a hsc student might read what he has wrote and believe it i really think one of the mods of the 4u forum should edit his posts so people know what hes saying isnt true or at least make a post saying no_arg is...

this was on: http://mathworld.wolfram.com/eApproximations.html a site from Wolfram Research do u really expect people to believe u over them

sorry, no_arg is just really pissing me off he knows his argument is untrue and is arguing it just to annoy others a hsc student might read his posts and believe it i think one of the moderators should edit his posts so people know what hes saying isnt correct