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wtf uni physics? It doesn't sound very hard for some reason...

Nop. The question just asked to express it in that form

In the hsc, can you use 3unit maths projectile motion? I cbf remembering all these formulas

5/3, -5/3, -18/12 = -3/2 and 8/12 = 2/3 Method, sub c and -c or whatever pronumeral you give it. Is this as hard as polynomials get? I haven't done it yet :D

All can be done with 2 unit methods

a+ 2d = 7 a+6d = 31 d=6 a=-5 -5 +7x6 =37

Oh yea. z + z_ is 2Re(z) I hate recalling stuff, but I hate having to calculate it

pretty sure that's the correct answer

No. I read your post before. You are absolutely right. ITT: fags discussing pens One of the most pointless threads ever

You magically introduced p in the denominator. Lol You're meant to think of that up really...I don't think any textbook has that labelled as a formula to remember

Our school only started learning trig. It takes time for us to grasp certain concepts. You already know everything and hence think everything is easy. This isn't the case for someone that's just learnt the content

New question Find the general equation(s) of the tangent to the circle x^2 + y^2 = 1

Chain rule Quotient rule Product rule Lol

the next one is too long to write

a) 1/4. Sub 2r into the formula. b) 1/16. [2(2r)]^2 = 16 c) Use kepler to find T. Then use 2pir/T

Pretty sure he meant = x^2 + xRe(z) + |z|^2 Comes from conjugate roots theorem.

-P +/- i(root p^2 - 4) / 2 Then just use root(x^2 + y^2) You'll get one

The last one gives it away. There is no displacement reaction there, so Z is more active than X. The 1st one shows X is more active than Y. So Z>X>Y. D

Oh..thought it might be related to the brute force method in hacking

Did you end up killing the equation? Brute force a type of trial and error? It's a bit of a computer term