Search results

I've never tried studying ahead, but year 11 is a practise for year 12 so instead of focusing on all subjects, focus on your weakest/ least strongest subjects, probably around 3, if u are capable u can do more and try to understand that module . Seems impractical to do all subjects in two weeks...

Simply Lim approaching 0 sin5x/x

Find the exact area bounded by the curves y=sinx any=cosx in the domain 0 less or equal to x less or equal 2pi “ Find the exact area enclosed by the curve y=sinx and the line y=1/2 for 0 less or equal to x less or equal 2pi ”

how come it changed to -3 and did not stayed as 1/3

integrate 4e^2-x e^-x/3

THANK YOUUU! didn't even think about using sin

a circle has a chord of 25mm with an angle of pi/6 subtended at the centre. Find, the length of the arc cut off by the chord . 1 dp.

Solve: tan^2x-1= 0 between 0 and 2pi

yep, but how do i derive those answers?

there is the basic table, but it doesn't mention the one's with divided by two.

Simplify cos( π/2 -X) tan (π/2 -θ) (Note: π= pi)

I know,i tried applying it but i was a bit off. Maths isn't my forte! (as you can tell), but i am trying my best! :)

For a certain garoh, the rate of change of y values with respect to its x- values is given by R= 3x^2 - 2x +1. If the graph passes through the point (-1,3). find the equation. b) The rate of change in velocity over time is given by dy/dt= 4t + t^2 - t^3 . If the initial velocity is 2 cm...

A particle moves so that the rate of change of distance D over time t is given by R= 2e^t -1. If D=10 when t=0, find d when t=3

how to differentiate loge(x-x^2) B) Find the equation of the curve tha f''x = 12ex^2 and a stationary point at (0,3)

Thanks INTEGRAND!!!!

its okay, thanxs for the help:) ur writing is soo neat :)

1) find the area between the curve y=ln (x), the y axis and the lines y=2 and y=4, correct to three significant figures

1. How do i integrate ln(x)- does it remain ln(x) 2. Find the volume of the solid formed when the curve y= 2/ root(2x-1) is rotated about the x- axis from x=1 and x=5, giving an exact answer

Find the Point of inflexion on the curve y= xlnx - x^2