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Meh...........

Ever heard of a thing called a "life"? Why don't you get one, rather than canvassing pointless trivialities and colouring a Maths forum with personal attacks better suited to a primary school playground? If you want to carry on like a 6-year old, however, I can solemnly asseverate that I issued...

I have a friend who hadn't even begun her major work by Week 3 of this term, and now she's closing in on 3000, edited and proof-read, words. I would advise you guys to take a step back, take a deep breath and realise that the words'll come if you relax, clear your mind and let it flow. I'm not...

Thanks! This stuff'll work wonders in my Economics revision!

Nah, more like that scaaary Darth Vader helmet from Star Wars... Remember that cuberoots of -ve numbers exist (eg. cubert(-8) = -2), so the graph can be drawn for f(x) < 0 (it is a function because the cubert of a number only ever has 1 real sol'n). First, f(-x) = cubert[1 - (-x)^2] =...

Edited after Ya, factorising to find a,b like ngai did, rather than the reverse, is probably the best way to go. You must've solved P(1-i) = 0, or P(1+i) = 0, for a,b, equating real and imaginary parts, to have found a,b before factorising. Also, to build on ngai's use of root-coeff...

Make sure the question read find "real" a and b, otherwise complex conj. doesn't apply If 1 +- i are roots, then [x-(1-i)], [x-(1+i)] are factors i.e. x^2 - 2x + 2 a factor Now, divide your p'nomial with known a,b by x^2 - 2x + 2 P(x) = (x^2 + 2x + 2)(x + 3) should be it P(x) =...

I don't mean to change the subject or anything, but I have an assessable Chem prac this Fri (HSC). I've been told that I can expect it to be quite a routine investigation, so I'm not too fazed. The experiment will concern equilibrium reactions. George, I have no probs, content-wise, but...

That's right. Why?

How does the HSC measure up to VCE and the QLD system, in terms of how kind it is on students? I know this is a highly subjective topic, and that this question is very broad, so I'm not expecting much more than brief overviews. If anyone could give me any facts/stats on this subject, however...

Combined Economics/Law To anyone doing this degree (these degrees), what's it like? The cut-off for HECS students is in the vicinity of 99.6% UAI - I take this to mean it is at least one of the most popular courses, but also one of the more prestigous on offer. Is this true? I'm looking at...

Really comes down to personal tastes and preferences, man. The course is a huge asset if you love Maths, and is especially handy if you want to take Maths to the tertiary level. From a practical point of view, 4U Maths scales the best out of the core HSC courses, making it great for your UAI if...

Yep, it is a pretty routine motion Q, but, yeah, it's at the harder end, so I'll run you through it ;) (a) For average v, you will need displacement, s and time of flight, t. First up, split your calculations into two parts: finding a value for the maximum height reached; and, calculating the...

Hey man, First up, write a neutral species equation for this reaction. This will give you the theoretical formula for mercury oxide. Assuming the use of Hg(II), it should flow like this: 2HgO(s) --(heat)--> 2Hg(s) + O2(g) ... [1] This tells you that the theoretical formula is HgO...

Had you paid closer attention to my wording, you would have regarded that I never brought your logic into question. I was neither debating the legitimacy of the process, nor the outcome. I was simply illustrating the misplacement of one small assumption on which you'd founded your reasoning...

Right on the mark ;) The compound's sodium bismuthate and it's often used as an oxidising reagent in experiments involving cation separation. In those scenarios, bismuth from the NaBiO3, in sol'n, oxidises cations less electronegative than itself. That's how it can sometimes have a valency of...

The sol'ns 1/2, -1/2 are incorrect. The statement is, on review, true for all real m, provided a couple of amendments are made. Other than that, there are no probs with my reasoning, so I'm not sure what's eating you. What I'm getting at there should be crystal clear. It's a simple...

Estel, Consider m = 1 Then, F(x) = 4(1+1)x^2 -4(1-1)x - 3 = 0 8x^2 - 3 = 0 (a difference of 2 squares, 2root2x and root3) Therefore, x = root3/2root2, -root3/2root2 = root6/4, -root6/4 m = 1 into your equation, however, gives discriminant = 16(1+1/2)^2 + 60 = 96 whence x = (-0 +-...

When are the next conferences?

Show that the roots of the equation are what?