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sorry but I still don't understand part 1, can someone mind explaining it for me

Hi i need help with this question: a, b, ab are the roots of the equation 4x^3 + 6x^2 + c = 0, where c is a non-zero constant. i. show that ab =/= 0 ii. Show that ab + a^2b + ab^2 = 0 and deduce the value of a + b iii. Show that ab = -0.5 iv. Solve the equation to determine the value of c

like what?? also are these easy to pick up or learn

how about physics, ancient history and economics?

I know maths can have up to 30 percent being tested, but how about subjects such as physics, chemistry, economics and ancient history?

. are you serious why not??

Yeah I will talk to my curiculum co-ordinator, but your saying that I have to do the preliminary assessment tasks that I had missed

any more comments please

in short the general solutions

well the best way is the graph, and i don't think it would hurt too much to draw one in exams

Hi guys, I currently I do 11 units, subjects are listed in my signature. Anyways I want to drop economics in year 12, therefore leaving me with 9 units and take up studies of religion 1 which leaves me with 10 units. The problem is that I haven't done the preliminary course for studies of...

ok the easiest way to get the answers is to draw the sin and cos graph, and see where they touch at either -1, 0 and 1

its obvoiusly possible to get a 95+ uai with any combination of subjects

dw, I don't think many people took year 7 - 10 seriously

I have a maths tutor because simply my maths teacher at school does not have the time to teach everyone at their own individual needs, this is when a maths tutor comes in.

ok im behind in year 11 physics, what topics, formulas, knowledge etc in year 11 physics is needed for year 12, as i will catch up in the holidays.

if u had this attitude earlier in year 12, your chances would be much higher

considering ur ranks, u have to get good marks in the hsc. Also keep trying, that is the most important thing

i managed to do question 15 which i was happy about, u had to write 3 simulatneous equations and solve for c , the answer was c = -2

ty question 6 left