Search results

re: HSC Chemistry Marathon Archive The bonding of the hydronium ion consists of covalent bonds between the oxygen and three hydrogen atoms. Since this ion carries a positive charge, this consequently means that there is one less electron ie. The total number of electrons in the ion is 8 not 9...

Re: Equilibrium expression and constant question Yeah I kinda realised my question wasn't anything too specific or restricted to a module ^____^'

Hey Sy, you know when you learnt, say complex numbers or integration, what did you first do? Did you research into the topic in textbooks, internet etc? Or did you skim the theory and just began applying?

Fair enough, though it could be that she is unable to cope with the pressure as well as others but she's already given her reason so yeah lulz.

It's not embarrassing tbh, I was in a similar situation to you (replace the smart cousins with smart sons and daughters of my father's friends/patients) so I can empathise with you to a considerable extent. From my experience in 2012, you just have to learn to put those issues aside and...

lel

At this point in time ie year 11, quite a few people aren't really sure about what they do so logically, they'd aim to achieve the highest they possibly can to have more flexibility in course choice. So perhaps fawun is stressing because although she is unclear about what career she wishes to...

Chemistry Calculation questions Hello everyone! :) Can anyone recommend to me/send me resources that mostly or purely consist of calculation questions? Thanks a lot.

No worries :)

Do you have any particular course/career that you would like to do or are passionate for?

Oh sorry! Log in to myuni -> Go to admin -> You should see a list of tabs. Go to financial information or enrolment variation. Sorry for unclear instructions, was going off the top of my head.

Log in to MyUni and go to "Financial information" and you should see your UoS. You can change your UoS by going to "Enrolment Variation". :)

Re: Equilibrium expression and constant question Ah thank you very much DamTameNaken! :) May I ask why you're already up to Industrial Chemistry?

:haha: You give me too much credit.

Yeah I agree with you on the exam part. But I still stick with weak acids producing moderately weak conjugate bases. They're not very weak nor are they strong to the extent of ionising completely but they're probably in the middle - higher end of the weak spectrum.

Equilibrium expression and constant question Alright, I got this question right but the intuition behind my method isn't clear to me. Okay so here's the working out: <a href="http://www.codecogs.com/eqnedit.php?latex=K = \frac{[H2O][CO]}{[H2][CO2]}" target="_blank"><img...

I'm not entirely sure man, like the textbook says that it produces a weak (not too weak) conjugate base. This is what I have found though I think the intuition behind a weak acid producing a weak conjugate base is that the conjugate base is a poor proton acceptor...

Bump!

A tad late Eg :haha:

No, I am certain that weak acids create relatively weak conjugate bases, not strong bases. HCOOH + NH3 -----> HCOO^- + NH4^+ We know NH3 is a weak base and hence it yields a weak acid. But since it is a weak acid, it is very unlikely that it will donate a proton to HCOO^-. If HCOO^- was...