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Maths is not a "wrote learn" subject, you have to understand the concepts in order to be able to do questions

The excess moles means that after a reaction has occurred and finished, there is still an amount of a substance left over in the reaction flask, whether it may be acidic or basic in nature. Hence why you use the excess moles to calculate the pH because that is the only thing that remains in the...

I reckon 2 past papers is not enough... You have to be constantly doing papers for all subjects to expose yourself to a variety of questions...

R = square root of (1^2 + (root3)^2) = 2. your angle is just tanA = root3. Therefore A = pi/3. 2cos(y+pi/3)

You can get a 99 like anomalous said, however you have to do extremely well in your other 8 units which may be hard (I don't know your capabilities) because generally when you look at raw marks for getting like 94 and 95 in a subject, there is a significant jump from raw marks to get 90, and...

My teacher has told me that they no longer award a mark for conclusions, so a short concluding sentence is suffice. You don't have to write a long one

Do advanced for year 11 and if you're struggling drop to standard in year 12. The scaling for both subjects are pretty much the same, advanced may be a little more, and you're better off getting a band 5 in standard then a band 4 in advanced. Plus if you think about it strategically in regards...

This question is so annoying! I cant even find solutions to the paper :(

Another perms and combs question haha, ruse paper (2003) All the letters of the word ENCUMBRANCE are arranged in a line. Find the total number of arrangements, which contain all the vowels in alphabetical order but separated by at least one consonant.

Dilute = 0.28mol/L Original = 2.8mol/L

True true haha :P

What i did was total combinations so 7! - (3x6!x2) There are three boys, and total number of ways arranging two of them together is 3x6!x2!

If 5*144 means 5x144 then i got 720 as well. but not too sure if correct.

you can have G G B G B G B or B G G B G B G, there's more arrangements to not allow two boys to be together. It just seems ambiguous and the way i did it seems dodgy

Find the number of ways in which 4 girls and 3 boys can be seated in a row so that no two boys are next to each other. Need confirmation to my answer.

ahh shit, i just realised it was sinx + cosx = 1. i misread the question and thought it was equal to 0.

A flame test would suffice as two different, distinguishable colours are produced by each ion. For example, when barium ions are sprayed into a flame, a green colour is observable. When calcium ions are sprayed into a flame, a brick red colour is observable. I believe there is no need for the...

pm me some please? :D

tan285 = -tan75 = -[tan(45+30)] = -(root3+1)/root3-1

Absolute legend for doing this!