Search results

Its Mod 5 content regarding gravitational stuff. LEO is low earth orbit satellites (closer from centre of earth and orbits earth like twice a day or smthg) and GEO is geostationary satellites (further from centre of earth and synchronised with earths motion)

Ig we'll just have to see, but I think 75 is still a little harsh since in other years (although more difficult) a 75 did manage to go to a mid B5.

You reckon? Cos 2023 was 72 to a b5 and I feel like they were either very similar in difficulty or this was a little more difficult in terms of some calculations.

Probably around there, I expect B5 to be around raw 70 -72

Chem is amazing, actually a subject that I might miss studying. Physics fr just get it done and over with please

They're gonna bring in some crazy calculation question. Their gonna involve circular motion of a planet that is has its ring at a 53 degree angle and and a projectile is shot off the planet and it hits the ring and deflects off and then another projectile is shot at the same angle and velocity...

I doubt it, I think you would be getting atleast a B5, probably a mid B5 and assuming some people even ranked below you could have performed decently fine, there is still a chance of B6 for you :)

How many people are in your cohort, if there is quite a large number then it is possible that others (people ranked lower than you) performed better than the two people above you. So there is still chance to get a B6. However, a very bad performance throughout your whole will affect your score...

Quality > Quantity (also I also wrote 3 pages + my handwriting is small). It will all be fine and they don't mark you on how much you wrote, they mark you on what you wrote. Its not like they start from 20 and go down to 0 (E.g. they don't take a mark for having less pages). Anyways, its out of...

I think Mod C is gonna be least harshly mark since they didn't provide an imaginative option. So they basically narrowed the range of thought and half the state wrote on technology, so its not easy to distinguish between the b5 and b6. So idk but I think Mod C gonna be most leniently marked :)

Lol I was hesitant putting B as well because I thought that was contradictory, but ended up putting it anyway.

No you just had to calculate their pH by plugging in the numbers. But since it wan't equal to that 1.151 or whatever it was, it can't be a strong acid and doesn't fully ionise. Btw which one was stronger?

I think that would be 1 more mark, and if you explain what the numbers in the h nmr just meant than that would have been another mark. So probs 4/7

Yeah, you needed to show that since Z only forms 1 product it is symmetrical and since number 3 is symmetrical that is Z and since Y forms 2 products it is asymmetrical and thus it is 1. The Titration data was only to split between X and (Y and Z). For X you could have just said that since it...

Thats Q38 Yeah you really didn't need to use everything, like I put the answers before showing anything, but then just ended up showing everything since if they've provided it you probably gotta show its importance

Like for titre volume if you match it (you have to use a mol ratio for Z btw) you get that Y and Z have the same titre volume. But since Z is symmetrical it is the third 1.

I mean thats fine as well. Either way you get the identity of the required species.

Nah you had to match titre volume using the concentrations they provided. I think.

Maybe two marks lost because it was just a simple c = n/V question, there was nothing much to do except for Z u had to use a mol ratio. Btw the order was Y, X, Z right or am i tripping

Boy your answer might be right lol. GPT saying its 0.53.