thats not correct, or at least not explained well. the method you described can only be used when you hypothesis is as followsleila said:avster:
for any circumstance (less than or greater than)
if t observe>t-critical(if it is positive number) or t observe<t-critical(if it is negative number)
we reject t observe
because in these two condition, the t observe area from the t-diagram is less than the t critical area, we have to reject them.
absolution* said:thats not correct, or at least not explained well. the method you described can only be used when you hypothesis is as follows
Ho: u= x
Hi: u (not equal) x
(1)leila said:and the method for reject or not reject is the same in ANY circumstance
question 57 b, c, dabsolution* said:(1)
Testing H0 : B= B0 against H1 :B< B0
In this case, we reject H0 for large, negative values of the t-statistic tc.
Using critical value: Let t¤ be critical value.
Then t¤ is the number that satisfies:
We reject H0 if tc < t¤.
(2)
Testing H0 : B = B0 against H1 : B > B0
In this case, we reject H0 for large, positive values of the t-statistic tc.
Using critical value: Let t¤ be critical value.
Then t¤ is the number that satisifes:
We reject H0 if tc > t¤.
(3)
Testing H0 : B = B0 against H1 : B (notequal)= B0
In this case, we reject H0 for large, absolute values of the t-statistic tc.
Using critical value: Let t¤ be critical value.
Then t¤ is the positive number that satisifes:
We reject H0 if |tc| > t¤
@s.m.i.t.h what part of qu57?
oh i think it was just an overly complex way of saying here's how to use continuous RV's.ToO LaZy ^* said:im assuming you're talking about those integrals..
i dont really remember him going inot detail with this stuff and it wasnt taught in our workshops..so i guess it PROBABILITY wont be examined.
i would know just the basics to be on the safe side. its relatively straight-forward.1Time4thePpl said:ok next question:
do we need to know stuff on uniform dist?
It was in the lecture notes, but i dont think we got taught it. Wasn't in the quizzes either. Not sure if its in the revision q's.
The only condition when two variables are independent are:absolution* said:i would know just the basics to be on the safe side. its relatively straight-forward.
my qu.: how do you know when to variables are independent when analysing a probability distribution table.
class with highest frequency id assumesarevok said:Just going through past quiz possible questions, any one know what the 'modal class' of a histogram is?