Let
Show all necessary working, please. V tricky.
Couldn't have asked for moreLet
where C is a constant
where is another constant
Same adding and subtracting the same thing trick as the previous question:Try:
let x = tan uTry:
this method is more intuitive and quicker I reckon esp if you know what the integral of inverse tan is off by heart.Same adding and subtracting the same thing trick as the previous question:
IBP on the first integral gives:
Second integral is just reverse chain rule
So in total:
This was the intended method.this method is more intuitive and quicker I reckon esp if you know what the integral of inverse tan is off by heart.
legit where did i go wrong, hella confused its probably one of the subs.This was the intended method.
Ngl I can’t even follow your solutionlegit where did i go wrong, hella confused its probably one of the subs.
or is this a possible alternate form? desmos ain't registering it for some reason tho
pls use LATEXlet x = tan u
x/ sec^2u / x^2 === > tan^3 u ===> tanusec^2u - tanu let tan u = z, z^2/2 + ln |cos u| lowkey messed it up, say where plz
or PAPERpls use LATEX
desmos not looking right, what happened in my subs bruhlegit where did i go wrong, hella confused its probably one of the subs.
or is this a possible alternate form? desmos ain't registering it for some reason tho
Super small typing error here.
botched the algebra.let x = tan u
x/ sec^2u / x^2 === > tan^3 u ===> tanusec^2u - tanu let tan u = z, z^2/2 + ln |cos u| lowkey messed it up, say where plz
Seen it b4 but didn’t know it was from Stanford!Really cool integral from stanford which a lot of people have probably seen before: