legit where did i go wrong, hella confused its probably one of the subs.This was the intended method.
or is this a possible alternate form? desmos ain't registering it for some reason tho
legit where did i go wrong, hella confused its probably one of the subs.This was the intended method.
Ngl I can’t even follow your solutionlegit where did i go wrong, hella confused its probably one of the subs.
or is this a possible alternate form? desmos ain't registering it for some reason tho
pls use LATEXlet x = tan u
x/ sec^2u / x^2 === > tan^3 u ===> tanusec^2u - tanu let tan u = z, z^2/2 + ln |cos u| lowkey messed it up, say where plz
or PAPERpls use LATEX
desmos not looking right, what happened in my subs bruhlegit where did i go wrong, hella confused its probably one of the subs.
or is this a possible alternate form? desmos ain't registering it for some reason tho
Super small typing error here.
botched the algebra.let x = tan u
x/ sec^2u / x^2 === > tan^3 u ===> tanusec^2u - tanu let tan u = z, z^2/2 + ln |cos u| lowkey messed it up, say where plz
Seen it b4 but didn’t know it was from Stanford!Really cool integral from stanford which a lot of people have probably seen before:
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thanks for picking that upSuper small typing error here.
wtf is this accounttfw you can't even do basic algebra smh
fuck latexmore integrals
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my lil bro apparentlywtf is this account
mmm yes sexy latex completedmore integrals
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more integrals
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the classic integral-calculator.com integral that no one bothers doing.mmm yes sexy latex completed
Thats as simple as it gets I think (you can usually simplify if the inverse is in the brackets) also try using \cos^{-1}(x) to getwhatsin term of u im having a bit of a mental breakdown
i do better latex smhwhatsin term of u im having a bit of a mental breakdown