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  1. barbernator

    HSC 2012 MX1 Marathon #2 (archive)

    Re: HSC 2012 Marathon :) |k|-arctan(|k|) celerysticks, does this cover all bases?
  2. barbernator

    HSC 2012 MX1 Marathon #2 (archive)

    Re: HSC 2012 Marathon :) (1 - pi/4) units squared
  3. barbernator

    HSC 2012 MX1 Marathon #2 (archive)

    Re: HSC 2012 Marathon :) sum1 else post some questions
  4. barbernator

    HSC 2012 MX1 Marathon #2 (archive)

    Re: HSC 2012 Marathon :) dats it. would rep but must spread first.
  5. barbernator

    HSC 2012 MX1 Marathon #2 (archive)

    Re: HSC 2012 Marathon :) Two of the roots of the equation x^3 + ax^2 + b = 0 are reciprocals of each other (a and b are real). i) show that the third root is equal to -b ii) show that a= b - 1/b iii) show that the two roots, which are reciprocals, will be real if -0.5 < = b < = 1/2
  6. barbernator

    HSC 2012 MX1 Marathon #2 (archive)

    Re: HSC 2012 Marathon :) We can find y. Heres the method for working out. After showing similar triangles and that shit, use the cos rule for the base triangle with angle 120 degrees. This will give us a relationship between alpha and beta. (the two unknown sides of that base triangle). But...
  7. barbernator

    HSC 2012 MX1 Marathon #2 (archive)

    Re: HSC 2012 Marathon :) yessssssssssssssssssssssss
  8. barbernator

    HSC 2012 MX1 Marathon #2 (archive)

    Re: HSC 2012 Marathon :) PM me if u want a clue, or the answer to work towards
  9. barbernator

    HSC 2012 MX1 Marathon #2 (archive)

    Re: HSC 2012 Marathon :) nope.
  10. barbernator

    HSC 2012 MX1 Marathon #2 (archive)

    Re: HSC 2012 Marathon :) cmon guys!!! you havent got the answer yet
  11. barbernator

    HSC 2012 MX1 Marathon #2 (archive)

    Re: HSC 2012 Marathon :) that diagram is correct
  12. barbernator

    HSC 2012 MX1 Marathon #2 (archive)

    Re: HSC 2012 Marathon :) zeeeee answer is not zat
  13. barbernator

    HSC 2012 MX1 Marathon #2 (archive)

    Re: HSC 2012 Marathon :) i guess so, final question in 1988 paper.
  14. barbernator

    HSC 2012 MX1 Marathon #2 (archive)

    Re: HSC 2012 Marathon :) A man 1.8m tall, standing due east of a street light notices that his shadow is 6.5m long. He walks on a bearing of 150 deg T from his position for a distance of 12 m and now finds his shadow is 9.1m long. Find the height of the street light above the ground level. (in...
  15. barbernator

    HSC 2012 MX1 Marathon #2 (archive)

    Re: HSC 2012 Marathon :) i have a booklet of past CSSA trials, im sure i can find something ;) have u done SHM yet?
  16. barbernator

    How's everyone coping?

    Oh and have a well balanced diet, exercise regularly, maintain frequent social activity, climb a mountain, go on a holiday, have a gf/bf, make the moneyyz and win masterchef.
  17. barbernator

    HSC 2012 MX1 Marathon #2 (archive)

    Re: HSC 2012 Marathon :) same thing, its an equation.
  18. barbernator

    How's everyone coping?

    whys erryone stressing? just come first in errything and ace the HSC and get 99.95 and its all good. No stress
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