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Haha ok i concede that it was a close finish :) nah we didn't. Really good day though, and I definitely know how to count to 5 lol.

here's a solution of question 10 courtesy of carrot!

ill do it tomorrow, i cbf to do it tonight

no quadrilateral of perimeter 24 can have an area 40. If there were no restrictions upon side length, the maximum area of a 24 unit quadrilateral would be 6x6=36 units squared ( when it is a square )

concentration, ppm in solution.

grats to sydney tech team, they ripped everyone

off the top of my head(i have not done any mechanics), assuming g=9.8, F=9.8sin(pi/3) N 120 degrees to the horizontal

i let f(x)=a+bx and solved. i dont get spirals way? EDIT: yes i do lol

your family are obv cunts if they get disown you for putting in effort.

Thats Redonkulous. Go to good school --> get same mark as person from bad school --> get better rank. DA FUQ

Re: HSC 2012 Marathon :) read back a page, there was multiple ways to solve the question. It was a difficult off the cuff question, that was easiest solved through that method

Re: HSC 2012 Marathon :) X1, in that vein, i call upon carrotsticks to clarify the thread name

Re: HSC 2012 Marathon :) guys, this is a marathon... once ewe answer a question ewe post one... otherwise we get nowhere!

you dont want general maths to count towards your atar now do you?

nobody he asked worked it out, he probably didnt ask everyone. I guess it is quite a worrying sign though

Im going with an early tip of state rank

lolwut

is your HSC really 2013??? im a bit skeptical

spiral always provides solutions, I should have said. One thing he has left unexplained is his GF(real or imaginary)

Re: HSC 2012 Marathon :) <a href="http://www.codecogs.com/eqnedit.php?latex=solve~for~x: x^2@plus;2x-4@plus;\frac{3}{x^2@plus;2x}=0" target="_blank"><img src="http://latex.codecogs.com/gif.latex?solve~for~x: x^2+2x-4+\frac{3}{x^2+2x}=0" title="solve~for~x: x^2+2x-4+\frac{3}{x^2+2x}=0" /></a>...