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Stay on topic please

I'm not exactly sure why you want to solve for the smallest k such that P(k+1)/P(k) < 0 when no such k exists given that P(k) and P(k+1) are probabilities and the total number of trials is m (so the largest possible value of k is m). The approach for (ii) is to find the largest value of k such...

I'd rather not reveal specifics but I am working in the finance industry.

Interesting that those near the top did consistently well in Q13 and Q14

Carrot just got a spike in PMs in the space of a few minutes lol

Have patience

In b4 they don't

lol Carrot

Solutions will be released a little bit later. They require a bit of time to finalise

I deliberately avoided the differentiation of GP for the solution because that would involve differentiation of complex numbers which is outside the scope of the syllabus (though the result would still work out if you did it this way)

Why?

Someone's impatient

*looks at this statement and looks at actual mark* ....

Meanwhile for Question 15...

2 Unit needs to be in a thread

I think this year's 3U is the hardest it has ever been. I think the 4U is more or less on par or slightly easier than last year.

We will address this in the marking. Either way the final result in the latter parts still work out.

Any particular questions you liked/disliked/want to know the answer to?

Now it's at Town Hall lol

Yes post BoS trial meat at Central station 6pm